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April 19, 2014

April 19, 2014

Posted by **Trixie** on Tuesday, April 13, 2010 at 9:40pm.

1,1,H + 1,1,p --> 2.1,H + ?

I thought initially the missing particle at the end would be either 0,-1,e or 0,1,e (beta emission/decay) but apparently it's not. I am not sure how to figure this out then...

- Chemistry -
**DrBob222**, Tuesday, April 13, 2010 at 10:29pmAre you trying to write this (but I'm putting the mass on top but on the other side)?

_{1}H^{1}+_{1}p^{1}==>_{2}H^{1}+ X

If so, the subscripts must add and the superscripts must add.

On th bottom w have 1+1 on the left which must add to 2 + 0 on the right. The top number is 1+1 on the left which must add to 1 + 1 on the right. Thus X must be_{o}X^{1}

I hope this comes out right because if I make any itsy bitsy slip, everything from then on gets printed wrong. Anyway, you identify X

- Chemistry -
**Trixie**, Tuesday, April 13, 2010 at 10:50pmI know they need to balance out on both sides. I am just confused because I am pretty sure it should be 0,+1, e ...e being X. Webassign is telling me this is wrong but if that's true I don't understand why and need that explained....

- Chemistry -
**DrBob222**, Tuesday, April 13, 2010 at 11:06pmI don't think so. An electron is -1e^0. I think oX^1 must be a neutron, right.

- Chemistry -
**Trixie**, Tuesday, April 13, 2010 at 11:13pmneutron was my first answer...i am using +1 e^0 to be a positron though, not electron.

- Chemistry -
**Trixie**, Tuesday, April 13, 2010 at 11:16pmOh i just realized how you typed the equation has the product flipped.

so it's 1,1,H + 1,1P --> 2,1H + ?

order is A,Z,X where A is mass and X is the particle or element

- Chemistry -
**DrBob222**, Tuesday, April 13, 2010 at 11:37pmI don't think I flipped anything.

Your 2,1,H is my 2H^1

Your 1,1,H is my 1H^1

If your 2,1,H is the same as my 2H^1, then the emitted product is a neutron oN^1.

- Chemistry -
**Trixie**, Wednesday, April 14, 2010 at 12:01amHmm...I don't know. My webassign is telling me it's not a neutron. Thanks

- Chemistry -
**DrBob222**, Wednesday, April 14, 2010 at 12:10amIf your equation is

1H^1 + 1p^1 ==> 1H^2, then X will be 1X^0 and that is a positron.

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