a player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds how much did the puck accelerate? I think it is 3m/s2.
can you show me how you got your answer?
can you show me how you got your answer for free.
To calculate the acceleration of the puck, we can use the formula for acceleration:
acceleration (a) = change in velocity (Δv) / time (t)
Given that the player increases the speed of the hockey puck by 6 m/s in 2 seconds, the change in velocity (Δv) is 6 m/s and the time (t) is 2 seconds.
By plugging these values into the formula, we can find the acceleration:
a = Δv / t
= 6 m/s / 2 s
= 3 m/s^2
Therefore, your calculation is correct. The hockey puck accelerates at a rate of 3 m/s^2.