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Chemistry

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The value of the equilibrium constant (Kp) as represented by the first chemical equation is 1.02 x 102 at 727 °C. Calculate the value of the equilibrium constant (Kp) for the second equation at the same temperature. Express answer in scientific notation.



2F(g) = F2(g)

F2(g) = 2F(g)

I'm not getting the math here, like how to mortify the first equation to equal it to the second one. [F]/[F]^2 = [F]^2/[F] ?

The answer is 9.8 x 10^-3

  • Chemistry - ,

    Wait never mind I figured it out.
    1/F = F so 1/102 right?

  • Chemistry - ,

    right.
    1/k = 1/1.02 x 10^2 = 9.8 x 10^-3

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