Posted by Angie on Tuesday, April 13, 2010 at 8:17pm.
A gamma ray (a highenergy photon of light) can produce a particle antiparticle pair, each particle with mass 8.68 MeV/c2 when it enters the electric field of a heavy nucleus: γ ! λ+ + λ− .
What minimum γray energy is required to accomplish this task?
I have searched but can't come up with a numerical answer in MeV units. Please Help

College Physics  bobpursley, Tuesday, April 13, 2010 at 9:17pm
You know the mass created: 2*8.68Mev/c^2
so energy= masscreated*c^2=2*8.68Mev

College Physics  Angie, Tuesday, April 13, 2010 at 9:52pm
thank you very, i did the calculations and it was simple math after your explanation..
i got answer as 17.36 MeV
=]
Answer This Question
Related Questions
 Physics help please  A gamma ray with 700KeV energy is ComptonScattered from ...
 physics  Gamma rays (γrays) are highenergy photons. In a certain nuclear...
 physics  Gamma rays (γrays) are highenergy photons. In a certain nuclear...
 Physics  Monochromatic light of wavelength, λ is traveling in air. The ...
 Physics  A photon having wavelength λ scatters off a free electron at A (...
 Physics  A gammaray photon produces an electronpositron pair, each with a ...
 physics  A gammaray photon produces an electronpositron pair, each with a ...
 Calculus  My question is finding the derivitive of y=((x+λ)^4)/(x^4+λ...
 Physics 30  A particle accelerated by a potential difference enters a velocity ...
 Physics  An alpha particle has a kinetic energy of about 5 MeV after they are ...
More Related Questions