How do I find the first five terms of each sequence?

a(1)=3, a(n+1)=a(n)+5

The things in the parentheses are subscripts.

You have a recursive formula

a(1) = 3
a(2) = a(1) + 5 = 8
a(3) = a(2) + 5 = 13

I am sure you can finish it now

Okay. Thank you. I tried it by myself while I was waiting for a response and wasn't sure if I did it right. But I did so, thanks again.

To find the first five terms of the sequence with the given recursion formula, you can use a recursive approach by substituting the values of each term one by one.

Given that the first term, a(1), is equal to 3, we can start by writing down the first term:
a(1) = 3

To find the second term, a(2), we substitute n = 1 into the recursion formula:
a(2) = a(1) + 5 = 3 + 5 = 8

Continuing this pattern, we can find the third, fourth, and fifth terms:
a(3) = a(2) + 5 = 8 + 5 = 13
a(4) = a(3) + 5 = 13 + 5 = 18
a(5) = a(4) + 5 = 18 + 5 = 23

Therefore, the first five terms of the sequence are:
a(1) = 3, a(2) = 8, a(3) = 13, a(4) = 18, a(5) = 23.