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April 18, 2015

April 18, 2015

Posted by **Abbey** on Tuesday, April 13, 2010 at 7:17pm.

k(2k+1) +(4(k+1)-1) = (k+1)(2(k+1)+1)

k^2+2k+3 For the right side?

- Math -
**Reiny**, Tuesday, April 13, 2010 at 7:20pmLS = k(2k+1) +(4(k+1)-1)

= 2k^2 + k + 4k + 4 - 1

= 2k^2 + 5k + 3

RS = (k+1)(2(k+1)+1)

= (k+1)(2k+2+1)

= (k+1)(2k+3)

= 2k^2 + 5k + 3

mmmhh?

- Math -
**Abbey**, Tuesday, April 13, 2010 at 9:10pmThank you!

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