A play is being put on at the school. There are 9 possible roles for girls who are trying out and 10 roles for boys who are trying out. If 16 girls and 12 boys try out, what percent of chance does one girl have of getting in? What percent does one boy have?

9/16 = 0.5625 = 56.25%

Now figure out the boys' chances.

83.33%?

Thank you

Right -- and you're welcome.

To find the chance or probability of a girl or boy getting a role in the play, we need to calculate the ratio of the number of available roles to the number of students trying out, and then express it as a percentage.

Let's start with the probability for a girl to get a role:
1. Determine the total number of roles available for girls, which is 9.
2. Next, find the total number of girls trying out, which is 16.
3. Divide the number of available roles by the total number of girls: 9 / 16 ≈ 0.5625.
4. To express this as a percentage, multiply 0.5625 by 100: 0.5625 * 100 = 56.25%.
Therefore, one girl has a 56.25% chance of getting a role in the play.

Now let's calculate the probability for a boy to get a role:
1. Determine the total number of roles available for boys, which is 10.
2. Find the total number of boys trying out, which is 12.
3. Divide the number of available roles by the total number of boys: 10 / 12 ≈ 0.8333.
4. To express this as a percentage, multiply 0.8333 by 100: 0.8333 * 100 = 83.33%.
Therefore, one boy has an 83.33% chance of getting a role in the play.