Posted by dan on Tuesday, April 13, 2010 at 4:56pm.
Question from the Classroom: 10
A student claims that the equation Ö(x) = 3 has no solution, since the square root of a negative number does not exist. Why is this argument wrong?

math  Jill, Tuesday, April 13, 2010 at 5:02pm
Because you could write the answer in imaginary numbers. So technically it does exist. Not sure if that's the exact answer you're looking for, but....
If you're thinking along the terms of a+bi
then the square root of 3 would be
1.73205...i
the dots are just the extra numbers. I assume you'd round it. But keep the curved i at the end.

math  Reiny, Tuesday, April 13, 2010 at 5:15pm
If you equation is
√x = 3 then
x = 9 is a real number solution to the equation

math  pem, Tuesday, April 13, 2010 at 5:40pm
isn't it an imaginary number
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