Sunday

December 21, 2014

December 21, 2014

Posted by **dan** on Tuesday, April 13, 2010 at 4:56pm.

A student claims that the equation (-x) = 3 has no solution, since the square root of a negative number does not exist. Why is this argument wrong?

- math -
**Jill**, Tuesday, April 13, 2010 at 5:02pmBecause you could write the answer in imaginary numbers. So technically it does exist. Not sure if thats the exact answer you're looking for, but....

If you're thinking along the terms of a+bi

then the square root of -3 would be

1.73205...i

the dots are just the extra numbers. I assume you'd round it. But keep the curved i at the end.

- math -
**Reiny**, Tuesday, April 13, 2010 at 5:15pmIf you equation is

√-x = 3 then

x = -9 is a real number solution to the equation

- math -
**pem**, Tuesday, April 13, 2010 at 5:40pmisn't it an imaginary number

**Answer this Question**

**Related Questions**

math - A student claims that the equation -x=3 has no solution, since the ...

math - A student claims that the equation has no solution, since the square root...

math - A student claims that the equation (-x) = 3 has no solution, since the ...

math - A student claims that the equation the !-x = 3 (square root of) has no ...

math - student claims that the square root of -x equals three has no solution, ...

MATH213 - A student claims that the equation√-x=3 has no solution, since ...

math - Jose claims that the equation \/ - x = 3 (this is read as the square root...

math/algebra - can someone check me and see if this is correct. (4x+1) + 3 = 0...

Math - i^6 = (i^2)^3 = (-1)^3 = -1 The square, not the square root of -1 is 1...

Algebra - I need help on these kinds of radical problems. Once I get the ...