Sunday

January 25, 2015

January 25, 2015

Posted by **lala** on Tuesday, April 13, 2010 at 4:01pm.

- Calculus -
**Reiny**, Tuesday, April 13, 2010 at 5:32pmf'(x) = (1/2)(tan(1-x))^(-1/2)*sec^2 (1-x)(-1)

= -(1/2) [tan(1-x)]^(-1/2) [sec(1-x)]^2

now we need the product rule, what a mess ...

f''(x) = -(1/2) [tan(1-x)]^(-1/2) (2)(sec(1-x)) (sec(1-x))(tan(1-x))(-1) + (-1/2)[sec(1-x)]^2 (-1/2)tan(1-x))^(-3/2)(sec^2(1-x))(-1)

check this carefully and see if you simplify by factoring. I can see all kinds of common factors, but find it hard to read my own typing, lol

**Answer this Question**

**Related Questions**

Calculus - I need to find the second derivative of y=x(x-1)^1/2. I found the ...

Maths Calculus Derivatives - Find the first derivative for the following ...

Calculus - find the derivative: d/dx int_a to x (a being the upper limit) of tan...

Applied Calculus - Find the first and second derivative of the function: x/(7x+...

Calculus - I need help with finding first and second derivative--simplify your ...

calculus - find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx ...

CALCULUS HELP - Find the second derivative for the function 5x^3+60x^2-36x-41 ...

Calculus : Derivative - If tan^-1(x^2-y^2/x^2+y^2) = a, prove that dy/dx = x(1...

calculus - Find the first and second derivative - simplify your answer. y=x/4x+1...

Calculus - R=M^2(c/2-m/3) dR/dM=CM-M^2 I found the derivative. Now how would I ...