# Chemistry

posted by on .

A student completes a titration by adding 12.0 milliliters of NaOH(aq) of unknown concentration to 16.0 milliliters of 0.15 M HCl(aq). What is the molar concentration of the NaOH(aq)?

• Chemistry - ,

Ð—Ð°Ð¿Ð¸ÑˆÐµÐ¼ ÑƒÑ€Ð°Ð²Ð½ÐµÐ½Ð¸Ðµ Ñ€ÐµÐ°ÐºÑ†Ð¸Ð¸:
NaOH + HCl = NaCl + H2O
C NaOH*V NaOH = C HCl*V HCl
Ð³Ð´Ðµ: C NaOH Ð¸ C HCl - Ð¼Ð¾Ð»ÑÑ€Ð½Ñ‹Ðµ ÐºÐ¾Ð½Ñ†ÐµÐ½Ñ‚Ñ€Ð°Ñ†Ð¸Ð¸ Ð³Ð¸Ð´Ñ€Ð¾ÐºÑÐ¸Ð´Ð° Ð½Ð°Ñ‚Ñ€Ð¸Ñ Ð¸ Ñ…Ð»Ð¾Ñ€Ð¸Ð´Ð° Ð²Ð¾Ð´Ð¾Ñ€Ð¾Ð´Ð° ÑÐ¾Ð¾Ñ‚Ð²ÐµÑ‚ÑÑ‚Ð²ÐµÐ½Ð½Ð¾, Ð¼Ð¾Ð»ÑŒ/Ð»; V NaOH Ð¸ V HCl - Ð¾Ð±ÑŠÐµÐ¼Ñ‹ Ñ€Ð°ÑÑ‚Ð²Ð¾Ñ€Ð¾Ð² Ð³Ð¸Ð´Ñ€Ð¾ÐºÑÐ¸Ð´Ð° Ð½Ð°Ñ‚Ñ€Ð¸Ñ Ð¸ ÑÐ¾Ð»ÑÐ½Ð¾Ð¹ ÐºÐ¸ÑÐ»Ð¾Ñ‚Ñ‹ ÑÐ¾Ð¾Ñ‚Ð²ÐµÑ‚ÑÑ‚Ð²ÐµÐ½Ð½Ð¾, Ð».
ÐœÐ¾Ð»ÑÑ€Ð½Ð°Ñ ÐºÐ¾Ð½Ñ†ÐµÐ½Ñ‚Ñ€Ð°Ñ†Ð¸Ñ NaOH Ñ€Ð°Ð²Ð½Ð°:
C NaOH*V = C HCl*V HCl/V NaOH = 0,016*0,15/0,012 = 0,2 Ð¼Ð¾Ð»ÑŒ/Ð»

We write the reaction equation:
NaOH + HCl = NaCl + H2O
C NaOH * V NaOH = C HCl * V HCl
where: C NaOH and C HCl - molar concentration of sodium hydroxide and hydrogen chloride, respectively, mol / l; V NaOH and V HCl - volumes of the solutions of sodium hydroxide and hydrochloric acid, respectively, l.
Molar concentration of NaOH is:
C NaOH * V = C HCl * V HCl / V NaOH = 0,016 * 0,15 / 0,012 = 0,2 mol / l