Thursday

April 17, 2014

April 17, 2014

Posted by **Anonymous** on Monday, April 12, 2010 at 11:44pm.

where s is the displacement in metres and t is the time in seconds. Find the absolute max and absolute min displacements.

- urgent calculus -
**Reiny**, Tuesday, April 13, 2010 at 12:31ams'(t) = 2cost + sint

= 0 for a max/min

sint = -2cost

sint/cost = -2

tant = -2

t = π - 1.107 = 2.0344 or

t = 2π - 1.107 = 5.176

s(2.0344) = 2.236

s(5.176) = -2.236

so the max is ...

and the min is ....

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