Posted by anonymous on Monday, April 12, 2010 at 9:52pm.
Add the probabilities that 0, 1, 2 or 3 components have failed. That sum will be the probability that the machine works.
The probability that none have failed is
P(0) = 0.8^7 = 0.210
The probability that one part has failed is
P(1) = 0.8^6*0.2*7 = 0.367
The probability that two parts have failed is P(2) (0.8)^5*(0.2)^2*[7!/(5!2!)] = 0.275
The probability that three parts have failed is P(3) = (0.8)^4*(0.2)^30*[7!/4!3!)] = 0.115
The sum of these probabilities is 0.967.
thank you so very much! you're my hero! =D
Related Questions
Elementary Statistics - A machine has 7 identical components which function ...
stat - a machine has 7 identical components which function independently. the ...
Statistics - Using formula P(x) = x/15 For each of the values x = 1, 2, 3, 4, ...
Statistics - Suppose that the probability distribution of a random variable x ...
Math - A company that produces a particular machine component has 3 factories, ...
Math - A company that produces a particular machine component has 3 factories, ...
Statistics - Suppose that the probability distribution of a random variable x ...
bus stats - A manufacturing company has 5 identical machines that produce nails...
statistics - A mini-computer system contains two components, A and B. The system...
stats - A manufacturing process has 100 customer orders to fill. Each order ...
For Further Reading