If 2.00L of nitrogen and 5.00L of hydrogen were allowed to react, how many liters of NH3 (g) could form? The condition of the gas collected were 745 mmHg and 22C.
1. Write the equation and balance it.
2. You can use liters directly to determine how much NH3 is made (atSTP).
3. Identify the limiting reagent. The easy way to do this is to determine liters NH3 from 2.00 L N2. Then determine liters NH3 from 5.00 L H2. The SMALLER value will the correct volume and the reagent producing that value will be the limiting reagent.
4. Then use (P1V1)/T1 = (P2V2)/T2 to correct for the non-standard conditions.