Posted by sarah on Monday, April 12, 2010 at 7:21pm.
The formulas represent the area of the triangle
Did you want an actual proof of the formula?
Hint: draw a perpendicular from P to QR, call it h
take sinR, then find the area by (1/2)base*height.
How do I actually proof the formula?
ok, follow my steps above
you now have a right-angled triangle with a height of h
sin R = h/PR = h/q
h = qsin R
Isn't the area of the triangle (1/2)(base)h
= (1/2)QRh
= (1/2)p(qsin R)
= (1/2)pq sin R as requested.
dropping perpendiculars from R and Q you can prove in the same way that
area = (1/2)rq sinP and (1/2)rpsinQ
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