Posted by johny g12 on .
Devon’s bike has wheels that are 27 inches in diameter. After the front wheel picks up a tack, Devon rolls another 100 feet and stops. How far above the ground is the tack?

math 
Reiny,
100 ft = 1200 inches
one rotation covers 27π or 84.823 inches
so the wheel went 1200/84.823 or 14.1471 rotations
We are interested in the .1471 part of the last rotation.
make a sketch of the circle, draw in vertical radius, and label an arc length of .1471(84.823) or 12.478 inches.
We need the central angle which subtends that arc of 12.478
from arc = rØ
we have
12.478 = 27Ø
Ø = .46215 radians
From the end of the arc, draw a horizontal cutting the radius to create a rightangled triangle
let h be the length form the centre of the circle to that horizontal
cos .46215 = h/27
h = 27cos.4615 = 24.16
so the nail is 27  24.16 or 2.8 inches above the ground.
You better check my arithmetic.