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Posted by **Esi** on Monday, April 12, 2010 at 6:40pm.

2. And: Given any triangle ABC, with sides a, b, and c opposite angles A, B,

and C, respectively, what can be said about the three ratios a/sinA , b/sinB

, and c/sinC ? This result is known as the Law of Sines.

- geometry -
**drwls**, Monday, April 12, 2010 at 8:31pm1. Side AC is also known as b, the side opposite angle B. Use the law of sines. The ratio b/sinB = 2R, where R is the radius of the circumscribed circle.

For a proof, see http://www.pballew.net/lawofsin.html

2. Those ratios are equal for any triangle.

- geometry -
**Esi**, Tuesday, April 13, 2010 at 12:12amthank you

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