Posted by pem on Monday, April 12, 2010 at 4:49pm.
So you have 0.600 g in 250 mL. That is 0.600/100 = 0.006 moles CaCO3. (I estimated the molar mass CaCO3; you need to confirm and update it.)
Molarity = moles/L = moles/0.250 L = ?
How many moles do you have in the 250. How many moles in 1/10th that?
yes the calcium carbonate has (MW= 100.09 g)hence the moles for CaCo3 is correct but how do you calculate the mole for calcium ion Ca2+
Don't you have 1 Ca^+2 ion for every mole CaCO3 there?
Let me redo that. Don't you have 1 atom Ca^+2 for every molecule CaCO3; done another way, don't you have 1 mole Ca^+2 for every mole CaCO3?
2HCl+CaCO3=CaCl2 + H2O + CO2... i think so....
I don't know why you need an equation. There is 1 mole of Ca +2 ions in every mole of CaCO3; therefore, the concn of CaCO3 and the concn of Ca +2 ion are the same. For that matter, C ion is the and CO3 ion is the same as CaCO3. The oxygen concn (although not there as a gas) is 3 times that.
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