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December 22, 2014

December 22, 2014

Posted by **Anonymous** on Monday, April 12, 2010 at 12:15pm.

-5y4(y5)2

15y7(y2)3

- Math -
**PsyDAG**, Monday, April 12, 2010 at 2:53pmIf you have a power of a power, multiply the two values.

y^5 = y to the fifth power.

Is your first formula = -5y^4 (y^5)^2 ?

If so, it = -5y^4 (y^10) = -5y^14

Now you try it with 15y^7 (y^2)^3 = ?

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