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July 23, 2014

July 23, 2014

Posted by **Joe** on Monday, April 12, 2010 at 8:41am.

2 tan x/1+tan^2 x = sin 2x

- Pre Calculus -
**Reiny**, Monday, April 12, 2010 at 8:49amOne of the variations of sin^x + cos^x = 1 is

1 + tan^2x = sec^2x

so

LS = [2(sinx/cosx)]/sec^2x

= (2sinx/cosx)(1/cos^2x)

= 2sinxcosx

= sin 2x

= RS

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