Posted by Mica on Monday, April 12, 2010 at 12:23am.
The remaining quadratic has no solution in the set of real numbers.
The value of b^2 - 4ac in the formula is negative, so we cannot take the √ of a negative number.
your only real solutions are x = 2 and x = appr. 3.68
When you first asked this question, you asked for the factors, you did not ask for a solution to the corresponding equation x^4-4x^3+16 = 0
That is how it was answered.
Related Questions
Algebra - I posted this problem last night and some one told me I was wrong. ...
Math(dispute to previous question) - 2)Name the sets of numbers to which 457 ...
algebra - I asked this question earlier and wasn't sure what the answer was...
Algebra - Using rational zero theorem find all rational zeros P(x)=3x^3+43x^2+...
Algebra - Trying to figure out how to find all numbers for which the rational ...
Calculus - This is a problem we did previously on a test; my answer was marked ...
Math 30 - A popular game show begins with the host reading a question to the ...
Precalculus - I'm HOPING this is the last problem I need help on.. :-/ List ...
physics - I asked this question before: if the force of 60 N is exerted on a 15 ...
10 grade chem - Ok people my daughter myself and my husband have been unable to ...
For Further Reading