Math factors
posted by Mica .
I asked this question previously, but I was told you were unable to get the answer with rational numbers. I asked my teacher, and he said we could use estimates.
y=x^44x^3+16
y=(x2)(x^32x^24x8)
so i used 3.68
and i got this (x2)(x3.68)(x^2+1.68x+2.1824)
Could someone help me finish?

The remaining quadratic has no solution in the set of real numbers.
The value of b^2  4ac in the formula is negative, so we cannot take the √ of a negative number.
your only real solutions are x = 2 and x = appr. 3.68 
When you first asked this question, you asked for the factors, you did not ask for a solution to the corresponding equation x^44x^3+16 = 0
That is how it was answered.