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March 1, 2015

Posted by **Mica** on Monday, April 12, 2010 at 12:23am.

y=x^4-4x^3+16

y=(x-2)(x^3-2x^2-4x-8)

so i used 3.68

and i got this (x-2)(x-3.68)(x^2+1.68x+2.1824)

Could someone help me finish?

- Math- factors -
**Reiny**, Monday, April 12, 2010 at 8:40amThe remaining quadratic has no solution in the set of real numbers.

The value of b^2 - 4ac in the formula is negative, so we cannot take the √ of a negative number.

your only real solutions are x = 2 and x = appr. 3.68

- Math- factors -
**Reiny**, Monday, April 12, 2010 at 8:45amWhen you first asked this question, you asked for the factors, you did not ask for a solution to the corresponding equation x^4-4x^3+16 = 0

That is how it was answered.

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