What is the pH of a solution in which 25 mL of .10 M NaOH is added to 15 mL of .10 M HCl?
I have calculated the amount of moles of each, but I'm not really sure where to go from there. Thanks!
moles NaOH = M x L = 0.1 x 0.025 = 0.0025
moles HCl = 0.015 L x 0.1 M = 0.0015
So if they react 1:1 (from the equation), which one will be used up? And which is the one in excess? The excess will determine the OH if it is NaOH or it will determine H if it is HCl. Then moles remaining of that reagent/L solution is M and go to pH or pOH from there.