Posted by Harold on Sunday, April 11, 2010 at 9:01pm.
make 2 columns, marked A and B
A eats 1/2 leaving 1/2 -- B eats 1/4 leaving 1/4
A eats 1/8 th leaving 1/8th -- B eats 1/16 th, leaving 1/16 th
So A eats 1/2 + 1/8 + 1/32 + ...
a Geometric series with a=1/2, r = 1/4
S∞ = a/(1-r) = (1/2)/(1 - 1/4)
= (1/2)/(3/4) = 2/3
So A eats 2/3 of the loaf
The clearly B must eat the missing parts or 1/3.
Do the others the same way.
All I need to know is how do you do part two (2)? Is there a summation formula that we can use?
(4/9)^(n-.5)
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