how many moles of solute are contained in each solution?

250 mL of a 0.55 M NaNO3 solution?

145 mL of a 4.0 M HNO3 solution?

6.5 L of a 2.5 M HCl solution?

moles = M x L

how many moles of solute are contained in each solution?

250 mL of a 0.55 M NaNO3 solution?

How many moles of solute are contained in each solution

350 mL of a 0.49M NaNO3 solution
14 mL if a 6.1 M HNO3 solution
2.1L of a 3.6 M HCI solution

To calculate the number of moles of solute in a given solution, you will need to use the formula:

moles of solute = Molarity x Volume (in liters)

Let's apply this formula to the given solutions.

1. 250 mL of a 0.55 M NaNO3 solution:
First, convert the volume from milliliters (mL) to liters (L):
Volume = 250 mL = 250/1000 L = 0.25 L

Now, use the formula:
moles of solute = 0.55 M x 0.25 L = 0.1375 moles of NaNO3

Therefore, there are 0.1375 moles of NaNO3 in 250 mL of a 0.55 M solution.

2. 145 mL of a 4.0 M HNO3 solution:
Convert the volume to liters:
Volume = 145 mL = 145/1000 L = 0.145 L

Using the formula:
moles of solute = 4.0 M x 0.145 L = 0.58 moles of HNO3

Therefore, there are 0.58 moles of HNO3 in 145 mL of a 4.0 M solution.

3. 6.5 L of a 2.5 M HCl solution:
In this case, no unit conversion is necessary, as the volume is already given in liters.

Using the formula:
moles of solute = 2.5 M x 6.5 L = 16.25 moles of HCl

Therefore, there are 16.25 moles of HCl in 6.5 L of a 2.5 M solution.