Which would produce greater number of moles of product: a certain amount of hydrogen gas reacting with oxygen gas to make water, or the same amount of hydrogen gas reacting with nitrogen gas to make ammonia? Why?
Write the two balanced equations and see.
2H2 + O2 ==> 2H2O
3H2 + N2 ==> 2NH3.
Use a convenient number of moles H2 to start (say 2 moles but you can pick any number as long as you use the same number for both equations). How much water will we get (in moles).
2 moles H2 x (2 moles H2O/2 moles H2) = 2 moles x (2/2) = 2 mole H2O.
You can do NH3 the same way and compare. Post your work if you get stuck.
help me. i don't understand
To determine which reaction would produce a greater number of moles of product, we need to compare the balanced chemical equations for both reactions.
The balanced equation for the reaction between hydrogen gas (H2) and oxygen gas (O2) to form water (H2O) is:
2H2 + O2 → 2H2O
According to the equation, for every 2 moles of hydrogen gas consumed, 2 moles of water are produced.
On the other hand, the balanced equation for the reaction between hydrogen gas (H2) and nitrogen gas (N2) to form ammonia (NH3) is:
3H2 + N2 → 2NH3
According to this equation, for every 3 moles of hydrogen gas consumed, 2 moles of ammonia are produced.
Comparing the two reactions, we can see that the reaction between hydrogen gas and nitrogen gas produces 2 moles of product (ammonia) for every 3 moles of hydrogen gas consumed. This is a higher ratio compared to the reaction between hydrogen gas and oxygen gas, which produces 2 moles of product (water) for every 2 moles of hydrogen gas consumed.
Therefore, the reaction between hydrogen gas and nitrogen gas to form ammonia would produce a greater number of moles of product compared to the reaction between hydrogen gas and oxygen gas to form water.
To determine which reaction would produce a greater number of moles of product, we need to look at the balanced chemical equations for both reactions.
The balanced equation for the reaction between hydrogen gas (H2) and oxygen gas (O2) to produce water (H2O) is:
2H2 + O2 → 2H2O
In this equation, 2 moles of hydrogen gas react with 1 mole of oxygen gas to produce 2 moles of water.
The balanced equation for the reaction between hydrogen gas (H2) and nitrogen gas (N2) to produce ammonia (NH3) is:
3H2 + N2 → 2NH3
In this equation, 3 moles of hydrogen gas react with 1 mole of nitrogen gas to produce 2 moles of ammonia.
By comparing the coefficients in the balanced equations, we can see that the reaction between hydrogen gas and nitrogen gas produces a greater number of moles of product. For every 3 moles of hydrogen gas, 2 moles of ammonia are produced, whereas the reaction between hydrogen gas and oxygen gas produces 2 moles of water for every 2 moles of hydrogen gas.
Therefore, the same amount of hydrogen gas reacting with nitrogen gas to make ammonia would produce a greater number of moles of product compared to reacting with oxygen gas to make water.