Posted by mohd on Sunday, April 11, 2010 at 3:57pm.
these are my three thermochemical equations
2Cu(s)+S(s) give Cu_2S(s) delta H 79.5 KJ
S(s)+O_2 give SO_2(g) 297 KJ
Cu_2S(s)+2O_2(g) give 2CuO(s)+SO_2(g)
how i calculate standard enthalpy of formation in Kj per mol of CuO(s)?
please don't give the answer only guid me please

chemistry  DrBob222, Sunday, April 11, 2010 at 4:06pm
Add equation 1 to the reverse of equation 2 to equation 3. That will give you twice the equation you want and you can take half of it later.
Add kJ/mole for equation to the negative of equation 2 to the kJ for equation 3. All of that together gives twice what you are looking for so divide the total by 2 and divide the equation by 2.

chemistry  mohd, Sunday, April 11, 2010 at 4:12pm
in front of last equation i forgat to wright the delta H .it is 527.5 KJ

chemistry  DrBob222, Sunday, April 11, 2010 at 4:14pm
That doesn't change anything. When you reverse an equation change the sign of delta H, otherwise leave it.
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