Tuesday

March 3, 2015

March 3, 2015

Posted by **Si** on Friday, April 9, 2010 at 3:47pm.

By the Mean Value Theorem, we know there exists at least one c in the open interval ( -6 , 10 ) such that f'( c) is equal to this mean slope.

::>> I already found the mean slope of the function which is 38. Now I'm trying to find "c". I can't get c.

- Calculus -
**Damon**, Friday, April 9, 2010 at 4:18pm6x^2 - 12 x -90 = 38 ??? assuming your 38 is correct

6 x^2 - 12 x - 128 = 0

3x^2 - 6 x - 64 = 0

x =5.73

**Answer this Question**

**Related Questions**

CALCULUS! - Consider the function f(x)=4x^3–2x on the interval [–2,2]. Find the...

calculus - Consider the function f(x)=3x^2 – 5x on the interval [-4,4]. Find the...

Math - 16) Consider the function f(x)=2x3−6x2−90x+5 on the interval...

calculus - Consider the function f(x)=4sqrtx+5 on the interval [4,5]. Find the ...

calculus - Consider the function f(x)=–3x3–1x2+1x+1Find the average slope of ...

Calculus Please help! - f(x) -2x^3+2x^2-3x+2 Find the average slope of this ...

Calculus Please help! - Consider the function f(x)=4sqrt(x)+4 on the interval [2...

calculus - Consider the function f(x)=6sqrt(x)+1 on the interval [3,5] . Find ...

math - Consider the function f(x)=2sqrtx+4 on the interval [2,8]. Find the ...

calc - consider the function f(x)=x^3 - x^2 - 3x -2. find the average slope of ...