What is the complete ionic equation for CaS(aq) +CuCl2(aq)=CuS(s)+CaCl2(aq)
Ca^2+(aq)+S^2−(aq)+Cu^2+(aq)+2Cl^−(aq)→CuS(s)+Ca^2+(aq)+2Cl^−(aq)
Oh, it's time for some chemical comedy! Here's the complete ionic equation:
Ca²⁺(aq) + S²⁻(aq) + 2Cu²⁺(aq) + 2Cl⁻(aq) ⟶ CuS(s) + Ca²⁺(aq) + 2Cl⁻(aq)
And here's a little chemistry joke for you: Why was the math book sad after reading this equation? It realized that it had too many problems to solve!
To write the complete ionic equation, we need to break down all the reactants and products into their respective ions.
The given reactants are CaS(aq) and CuCl2(aq), which indicate that they are dissolved in water (aq stands for aqueous).
CaS dissociates into Ca^2+ and S^2- ions:
CaS(aq) -> Ca^2+(aq) + S^2-(aq)
CuCl2 dissociates into Cu^2+ and 2Cl- ions:
CuCl2(aq) -> Cu^2+(aq) + 2Cl-(aq)
The complete ionic equation can now be written as:
Ca^2+(aq) + S^2-(aq) + Cu^2+(aq) + 2Cl-(aq) -> CuS(s) + Ca^2+(aq) + 2Cl-(aq)
However, notice that the Ca^2+ and Cl- ions do not participate in the reaction since they appear as both reactants and products on both sides of the equation. Therefore, we can write the net ionic equation, which represents only the species involved in the reaction:
Net Ionic Equation: S^2-(aq) + Cu^2+(aq) -> CuS(s)
In the net ionic equation, we eliminate the spectator ions (Ca^2+ and Cl-) and focus on the essential species involved in the reaction, which are S^2- and Cu^2+.
I am not sure as to find out the charges on each of the spectator ions?
The net ionic equation is:
Cu^+2(aq) + S^-2(aq) ==>CuS(s)
You can add the spectator ions to make it a complete ionic equation.
The complete ionic equation is:
Ca^2+(aq)+S^2-(aq)+Cu^2+(aq)+Cl^-(aq)->CuS(s)+Ca^2+(aq)+Cl^-(aq)