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December 18, 2014

December 18, 2014

Posted by **Me** on Thursday, April 8, 2010 at 1:53pm.

- math -
**Reiny**, Thursday, April 8, 2010 at 3:25pmlooks like you did this ..

first no ---- x

second no -- y

third no ----x+y

now... " The sum of twice the first, three times the second, and twice the third is 7"

2x + 3y + 2(x+y) = 7

2x + 3y + 2x + 2y = 7

4x + 5y = 7 (#1)

also ... "The third number is 3 more than the first"

x+y = x+3

y = 3

back in #1

4x + 5(3) = 7

4x + 15 = 7

4x = -8

x = -2

first no -- -2

2nd no -- 3

3rd no -- 1

Check:

is the third the sum of the first two ? YEAH

is twice the first plus three times the second and twice the third is 7 ?

(-4 + 9 + 2 = 7 YEAH)

is the third 3 more than the first ?

1 is indeed 3 more than -2

YEAHHH

- math -
**Anonymous**, Thursday, April 8, 2010 at 6:43pmuhhh

- math -
**Me**, Friday, April 9, 2010 at 2:50pmDear Reiny! U r a life-saver! Is there a short cut to how can I set the question or change word problems into math one? It seems that this is my problem! Also, why did my way worked as well with different answers? My answers satisfied all equations as well. Many thanks.

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