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August 22, 2014

August 22, 2014

Posted by **Moe** on Thursday, April 8, 2010 at 1:43pm.

- Pre-Cal -
**drwls**, Thursday, April 8, 2010 at 1:50pm22920 years is exactly 4 half-lives, so the number of nuclei is 2^4 = 16 times less. That will leave 1000/16 = 67 C14 atoms.

The relationship of the decay constant (k) and the half-life (T1/2) is:

k = 0.693/(T1/2)

so k = 1.21*10^-4 years-1

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