Posted by joelle on Thursday, April 8, 2010 at 11:32am.
Area = πr^2
dA/dt = 2πr(dr/dt)
for the given data
dA/dt = 2π(150)(.1) m^2/min
= 94.25 m^2/min
Volume = Areax height = Ah
dV/dt = A(dh/dt) + h(dA/dt)
so when r = 150, A = π(150)^2 = 22500π
dV/dt = 0 (it remains constant) and
h = .02
0 = 22500π(dh/dt) + .02(94.25)
dh/dt = - .02(94.25)/22500π
= - .000026667 m/min
check my arithmetic
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