Post a New Question


posted by .

In an experiment, 23.0 g of ice at –25°C is converted into steam with a temperature of 124°C. How much heat is required for the process? The following data may be of use:
vap = 2260 J/g; Hfus = 334 J/g; Cp(ice) = 2.06 J/g • °C; Cp(water) = 4.18 J/g • °C;
Cp(steam) = 1.99 J/g • °C

  • Chemisty -

    q1 = heat to move ice from -25 C to zero C.
    q1 = mass ice x specific heat ice x delta T.

    q2 = heat to melt ice (change H2O solid to H2O liquid at zero degrees.)
    q2 = mass ice x heat fusion.

    q3 = heat to move liquid water from zero degrees C to 100 C.
    q3 = mass x specific heat water x delta T.

    q4 = heat to convert liquid water at 100 C to steam at 100 C.
    q4 = mass x heat vaporization.

    q5 = heat to move steam from 100 C to 124 C.
    q5 = mass x specific heat steam x delta T.

    Total q = q1 + q2 + q3 + q4 + q5.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question