Posted by piper on .
With time, t, in minutes, the temperature, H, in degrees Celsius, of a bottle of water put in the refrigerator at time t=o is given by
H = 4 + 16e-.02t
How fast is the water cooling initially? After 10 minutes? Include units in your answer
Do you have a typo?
Should it not be H = 4 + 16e^(-.02t) ?
if so, then ....
dH/dt = - .32e^(-.02t)
Initially means t = 0
dH/dt = -.32e^0 = - .32° / minute
dH/dt = -.32e^(-.2) = -.26° / min
check my arithmetic