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March 27, 2015

March 27, 2015

Posted by **piper** on Thursday, April 8, 2010 at 11:04am.

H = 4 + 16e-.02t

How fast is the water cooling initially? After 10 minutes? Include units in your answer

- Math -
**Reiny**, Thursday, April 8, 2010 at 11:13amDo you have a typo?

Should it not be H = 4 + 16e^(-.02t) ?

if so, then ....

dH/dt = - .32e^(-.02t)

Initially means t = 0

dH/dt = -.32e^0 = - .32° / minute

when t=10

dH/dt = -.32e^(-.2) = -.26° / min

check my arithmetic

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