Posted by Math factoring on Thursday, April 8, 2010 at 10:44am.
Can someone factor this for me?
y=x^44x^3+16
i could only get up to:
y=(x2)(x^32x^24x8)

Mica  Reiny, Thursday, April 8, 2010 at 11:08am
That's as far as you can go using rational numbers
(I ran x^32x^24x8 = 0 through my "cubic equation solver and got one messy real root and 2 complex roots)
http://www.1728.com/cubic.htm

Mica  Math factoring, Thursday, April 8, 2010 at 11:11am
would there be another way to find the x intercepts? Cause that's what i was trying to achieve

Mica  Reiny, Thursday, April 8, 2010 at 11:16am
you could sketch it and see appr. where it crosses the xaxis.
let f(x) = x^3  2x^2  4x  8
If there are any rational factors, then test for
f(x) = 0 using x = ±1, ±2,±4, and ±8
none work, so there are no rational factors.
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