Posted by **Ayodele** on Thursday, April 8, 2010 at 7:32am.

Pls help me out.

Four positive and equal charges are located dt the corners of a square of side 20cm.if each charge has a magnitude 2microcoulumb,calculate the force acting on the charge at the lower left corner of the square.

- physics -
**bobpursley**, Thursday, April 8, 2010 at 9:45am
Symettry makes the problem go away.

On the adjacent corners: F=kqq/s^2 * cos45

note that you resolve the force into two components, one component in the direction of the diagonal (above), and a perpendicular. However, the perpendicular to the normals from each corner cancel each other, as they are opposite directions. So you are left with the forces from corners in the direction of the normal

Fcorners=2*kqq/s^2 *cos45

now add the force from the diagonal charge.

Fdiag=kqq/(s*sqrt2)^2=1/2 kqq/s^2

add that to Fcorners, and you have it.

Make certain you understand this problem, you will see it again.

## Answer This Question

## Related Questions

- Physics 2 - four equal-magnitude (4uc)charges are placed at the four corners of ...
- Physics - 1.There are four charges, each with a magnitude of 2.5 µC. Two are ...
- Physics - Four point charges are located at the corners of a square with sides ...
- Physics - Four charges are located at the corners of a square as shown below. ...
- physics - Three equal positive point charges of magnitude Q = 8.00ì C are ...
- physics - Three equal positive point charges of magnitude Q = 4.00ì C are ...
- Physics - Two point charges, one of +3.00 10-5 C and the other -5.00 10-5 C are ...
- Physics - There are four charges, each with a magnitude of 2.65 microcoulombs. ...
- Physics - The figure shows four electrical charges located at the corners of a ...
- physics - consider the arrangement of four +20 microCouloumb point charges ...

More Related Questions