Posted by anonymous on Thursday, April 8, 2010 at 12:34am.
The (base) = 0.210 M aniline.
The (acid) = 8.40 g/molar mass aniline hydrochloride (gives you moles) and that divided by 0.750 L = M
i keep getting docked off. im getting 5.00 but its wrong? the pka is 4.61978 and adding it to .38 for 5. -.-
Using your pKa I get 5.00 also. The only thing I can suggest is that you look up pKa again. My text gives a slightly different number of 4.59 which is enough to make pH = 4.97 or so.
Related Questions
chemistry - What is the pH of a solution prepared by dissolving 8.40 g of ...
chem - 1. What is the [K+] of a solution prepared by dissolving 0.140 g of ...
Chemistry - Find the pH of a solution prepared by taking a 50.0 mL aliquot of a ...
Chemistry - Glycine amide hydrochloride (BH+) FM 110.54, pKa 8.20 Glycine amide...
chemistry - Q.1 What will be the pH at the equivalence point during the ...
Chemistry - A solution is prepared by dissolving 50.0 g of pure HC2H3O2 and 20.0...
chemistry - What is the pH of a solution prepared by dissolving 1.533 g HCl in ...
Chemistry - Calculate the pH of the following buffer solutions: a) a solution ...
chemistry - What is the pH of a solution prepared by dissolving 12.2 g of ...
Chemistry - Calculate the pH and pOH of a solution prepared by dissolving 0.93 g...
For Further Reading