Ions are electrically charged particles that are formed when certain compounds are dissolved in water. These solutions will conduct electricity. The Swedish scientist Svante Arrhenius coined the term ion (which means wanderer) to explain why solutions of electrolytes will conduct an electric current. When an electrolyte forms into a solution, it dissolves or dissociates into ions, a process called ionization. If a substance does not ionize, it will not conduct an electric current. Electrolytes include most acids, bases, and salts. Some conductors include hydrogen and sodium chloride, copper sulfate, and potassium nitrate. Substances that are not electrolytes include distilled water, sugar water, and most organic compounds. Which of the following is a nonelectrolyte?


A) H 2 SO 4 (sulfuric acid)
B) HCL (hydrochloric acid)
C) C 3 H 8 (propane gas)
D) NaCl (table salt)

hcl please help me idk those answer

To determine which of the given substances is a nonelectrolyte, we need to understand the properties of electrolytes and nonelectrolytes. Electrolytes are substances that dissolve in water to form ions, which can conduct electricity. Nonelectrolytes, on the other hand, do not dissociate into ions when dissolved in water and, therefore, do not conduct electricity.

Looking at the options:

A) H2SO4 (sulfuric acid): Sulfuric acid is a strong acid and dissociates into ions when dissolved in water, making it an electrolyte.

B) HCl (hydrochloric acid): Hydrochloric acid is also a strong acid, and like sulfuric acid, it dissociates into ions when dissolved in water, making it an electrolyte.

C) C3H8 (propane gas): Propane gas is a covalent compound and does not dissociate into ions when dissolved in water. Therefore, it is a nonelectrolyte.

D) NaCl (table salt): Sodium chloride is an ionic compound, and when dissolved in water, it dissociates into sodium ions (Na+) and chloride ions (Cl-). Therefore, it is an electrolyte.

Based on these explanations, the correct answer is C) C3H8 (propane gas) as it is a nonelectrolyte.