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what volume of oxygen gas is needed to completely combust 0.202 L of butane (C4H10) gas?

  • chemistry - ,

    1. Write the equation and balance it.
    2C4H10 + 13O2 ==> 8CO2 + 10H2O

    2.You CAN go through the general stoichiometric solution; however, when everthing is in the form of gases, 2 moles C4H10 gas will required 13 moles O2 gas or
    0.202 L x 13/2 = ?? L. The conversion is L to L.

  • chemistry - ,

    .031 L 0xygen

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