a 150ml sample of wetlands water requires 25.00 mL of a 0.0250 MH2SO4 solution for neutralization. Calculate the molarity of CaCO3 in the sample
Hmmmmm. There better not be much CaCO3 in the sample, limestone is not soluble.
.0250M*2*25ml=Msample*2*150
Msample=.0250* 1/6 Moles/liter
To calculate the molarity of CaCO3 in the sample, we will use the concept of acid-base neutralization reaction. From the information given, we can assume that the neutralization reaction is as follows:
H2SO4 + CaCO3 -> CaSO4 + H2O + CO2
According to the balanced equation, one mole of H2SO4 reacts with one mole of CaCO3.
To find the moles of H2SO4 used for neutralization, we can use the following formula:
moles of H2SO4 = Molarity of H2SO4 x Volume of H2SO4 (in liters)
Given that the volume of the H2SO4 solution used is 25.00 mL, we need to convert it to liters by dividing by 1000:
Volume of H2SO4 = 25.00 mL / 1000 = 0.0250 L
Using the given molarity of the H2SO4 solution as 0.0250 M, we can calculate the moles of H2SO4 used:
moles of H2SO4 = 0.0250 M x 0.0250 L = 0.000625 moles
Since the reaction is 1:1, the moles of CaCO3 present in the 150 mL sample is also 0.000625 moles.
To find the molarity of CaCO3, we need to divide the moles of CaCO3 by the volume of the sample in liters:
Molarity of CaCO3 = moles of CaCO3 / Volume of Sample (in liters)
Given that the volume of the sample is 150 mL, we need to convert it to liters by dividing by 1000:
Volume of Sample = 150 mL / 1000 = 0.150 L
Calculating the molarity of CaCO3:
Molarity of CaCO3 = 0.000625 moles / 0.150 L = 0.00417 M
Therefore, the molarity of CaCO3 in the sample is 0.00417 M.
To calculate the molarity of CaCO3 in the wetlands water sample, we need to use the concept of stoichiometry. Here are the steps to follow:
1. Write the balanced chemical equation for the neutralization reaction between CaCO3 and H2SO4.
CaCO3 + H2SO4 → CaSO4 + H2O + CO2
2. Find the number of moles of H2SO4 used for neutralization.
Given that 25.00 mL of 0.0250 M H2SO4 solution was used, we can calculate the number of moles using the formula:
Moles of H2SO4 = Volume (in L) × Molarity
Moles of H2SO4 = 0.0250 L × 0.0250 M = 0.000625 mol
3. Use stoichiometry to find the number of moles of CaCO3.
From the balanced chemical equation, we can see that the stoichiometric ratio between H2SO4 and CaCO3 is 1:1. This means that for every mole of H2SO4 used, one mole of CaCO3 is present in the water sample.
Therefore, the number of moles of CaCO3 in the sample is also 0.000625 mol.
4. Calculate the molarity of CaCO3 in the sample.
Molarity of CaCO3 = Moles of CaCO3 / Volume of Sample (in L)
Since the volume of the sample is given as 150 mL, we need to convert it to L.
Volume of Sample = 150 mL = 0.150 L
Molarity of CaCO3 = 0.000625 mol / 0.150 L ≈ 0.00417 M
Therefore, the molarity of CaCO3 in the wetlands water sample is approximately 0.00417 M.