If the initial pressure of SO3(g) is 4.775 atm, calculate the % of SO3(g) left over after the reaction reaches equilibrium according to the balanced equation. The value of Kp at 1000 K is 24.40. The initial pressure of the reaction products is 0 atm.

2SO3(g) = 2SO2(g)+O2(g)

Unit Conversions
K = C + 273
i have no clue on this problem on how to find percent

There is no need for you to have K=C=273 because you have nothing in Celcius. But 1000k is 24.40 and the pressure is at 0 atm

Ok

Ip-4.775
SO3 grams
1000k is 24.40

Your looking for percent compisition.

So you have to get

S-32.066x1= 32.06/32.06=??
O-16.00x3= 48/32.06=??

Then you get the answer the the nearest whole.
Then you should get a ratio.

can you be clearer a bit, i gont get why you try to find

S-32.066x1= 32.06/32.06=??
O-16.00x3= 48/32.06=??

why is 32.06/32.06, where did that number come from

we don't need to use 4.775 and 24.4 to solve this?

I never used those numbers, and you got the 32.06 because you need to divide each number by the smallest number of moles.

I hope you get it, im getting off.

004200 i need to changed to scientific notation

To find the percent of SO3(g) left over after the reaction reaches equilibrium, you need to calculate the equilibrium partial pressure of SO3 and then compare it to the initial partial pressure of SO3.

Here's the step-by-step process:

1. Start with the balanced equation: 2SO3(g) = 2SO2(g) + O2(g)

2. Write the expression for the equilibrium constant, Kp, using the partial pressures of the products and reactants:
Kp = (PO2)(PSO2)^2 / (PSO3)^2

3. Since the initial pressure of the reaction products is 0 atm, you can ignore the partial pressures of SO2 and O2 in the equation. The expression simplifies to:
Kp = (PSO2)^2 / (PSO3)^2

4. Rearrange the equation to solve for the equilibrium partial pressure of SO3:
(PSO3)^2 = (PSO2)^2 / Kp

5. Take the square root of both sides to solve for the equilibrium partial pressure of SO3:
PSO3 = sqrt((PSO2)^2 / Kp)

6. Substitute in the given values:
Initial pressure of SO3 (Pinitial_SO3) = 4.775 atm
Kp = 24.40

7. Calculate the equilibrium partial pressure of SO3:
PSO3 = sqrt((0)^2 / 24.40) (since Pinitial_SO3 = 0 atm and the initial pressure of the products is 0 atm)

8. Simplify the expression and calculate:
PSO3 = sqrt(0) = 0 atm

9. The equilibrium partial pressure of SO3 (PEquil_SO3) is 0 atm, which means that 100% of the SO3 has reacted. Therefore, there is 0% of SO3 left over.

To summarize, after performing the calculations, it is determined that the percent of SO3(g) left over after the reaction reaches equilibrium is 0%.