Monday

October 20, 2014

October 20, 2014

Posted by **looking for someone to varify my work please** on Tuesday, April 6, 2010 at 3:56pm.

Question: Find the margin of error E for a 90% confidence interval.

Round your answer to the nearest hundredths.

Answer:

n = 77, 492, σ = 34, zc = 1.645

1.645 x 34/√77 = 6.37

Question: Construct a 90% confidence interval for the mean life, µ of all Twinkle

bulbs.

Answer:

n = 77, 492, σ = 34, zc = 1.645

492 – 6.37 = 485.63

492 + 6.37 = 498.37

485.63 < µ < 498.37

**Answer this Question**

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