Posted by **Dave** on Tuesday, April 6, 2010 at 2:51pm.

If the price of electrical enegy is $0.10 per kilowatt *hour, find the cost of using electrical energy to heat the water in a 12.0m * 9.00m * 1.5m swimming pool from 15 degrees C to 27 degrees C.

So the change in temperature is 285.15 , the volume is 162m^3, the specific heat capacity (c) is 4.186 [J/kg*degrees C]. Please and Thanks.

- Physics Help Please! -
**Not gonna get an answer**, Tuesday, April 6, 2010 at 4:25pm
You're not going to get an answer here, I've tried this site, and everytime, I get the wrong answer or no one responds.

- Physics Help Please! -
**Chris**, Tuesday, April 6, 2010 at 4:34pm
The change in temperature is 12 deg C if it rises from 15 to 27 degrees.

1. Find the mass of water from volume of water times its density.

2. Find the heat in Joule needed from Q=mct where m is mass of water, c is specific heat capacity and t is rise in temperature.

Then the cost.

3. One kilowatt hour is

1000W x 60(min) X 60(sec) Joules.

4. Then find how many of these you need to heat that water.

5. Each one costs $0.1

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