Post a New Question

physical chemisry

posted by on .

Estimate the freezing point of 150 cm3 of water sweetened with 7.5g of sucrose
(C12H11O22). (Kf for water is 1.86 K kg mol-1; density of water is 1gcm-3)

  • physical chemisry - ,

    moles sucrose = grams/molar mass. Solve for moles.
    molality = moles sucrose/kg solvent. Solve for molality.

    delta T = Kf*molality.
    solve for delta T and from there the freezing point.

  • physical chemisry - ,

    6.11*10^-5 K

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question