Posted by Macy on Tuesday, April 6, 2010 at 10:00am.
From your given information,
r = 6,380,000 + 200,000 = 6,580,000 m or
....6,380 + 200 = 6,580 km.
The velocity required to maintain a circular orbit around the Earth may be computed from the following:
Vc = sqrt(µ/r)
where Vc is the circular orbital velocity in feet per second, µ (pronounced meuw as opposed to meow) is the gravitational constant of the earth, ~1.40766x10^16 ft.^3/sec.^2, and r is the distance from the center of the earth to the altitude in question in feet. Using 3963 miles for the radius of the earth, the orbital velocity required for a 250 miles high circular orbit would be Vc = 1.40766x10^16/[(3963+250)x5280] = 1.40766x10^16/22,244,640 = 25,155 fps. (17,147 mph.) Since velocity is inversely proportional to r, the higher you go, the smaller the required orbital velocity.
Insert your data to derive your orbital velocity.
Related Questions
Physics - A satellite of mass 220 kg is launched from a site on Earth's ...
Physics - A satellite of mass 210 kg is launched from a site on Earth's ...
Geometry - A satellite has-recently been placed in a nearly circular orbit 2000 ...
physics - Estimate the energy required from fuel to launch a 1465 kg satellite ...
Physics help PLZ!! - Estimate the energy required from fuel to launch a 1465 kg ...
physics - Two Earth satellites, A and B, each of mass m, are to be launched into...
Math WORD PROBLEM - The time in hours it takes a satellite to complete an orbit ...
physics - Two Earth satellites, A and B, each of mass m, are to be launched into...
physics - A 20000 kg satellite is launched from the surface of saturn and put ...
geometry - A satellite in a nearly circular orbit is 2000 km above Earth's ...
For Further Reading
