Posted by **Roy** on Tuesday, April 6, 2010 at 8:20am.

Prove that the limit as n approaches infinity of ((n!)^2)/(2n)! is 0.

I'm thinking that you have to use the squeeze theorem, but I'm not quite sure how. help please?

## Answer this Question

## Related Questions

- calculus - Prove that the limit as n approaches infinity of ((n!)^2)/(2n)! is 0...
- calculus - Suppose that f(x) is bounded: that is, there exists a constant M ...
- calculus - It is known that x 2 + 4x ≤ f(x) ≤ -x 2 -4x the interval...
- Calculus - I'm supposed to find the limit as x approaches infinity of (2-x-sinx...
- Math-Calculus - Hi, I am trying to figure out what the limit as h approaches 0 ...
- Help with one limit - I'm asked to find the limit as n approaches infinity of...
- Calculus - Following 2 questions are from a book at a point where L’Hopital’s ...
- Calculus - Following 2 questions are from a book at a point where L’Hopital’s ...
- calculus - Suppose that f(x) is bounded: that is, there exists a constant M such...
- Calculus - Find limit as x approaches 1 5/(x-1)^2 A. 0 B. Negative infinity C. 5...