Posted by **Michael** on Tuesday, April 6, 2010 at 1:27am.

A projectile is shot straight up from the earth's surface at a speed of 1.20×104 KM/HR.

How high does it go?

- Physics -
**drwls**, Tuesday, April 6, 2010 at 1:35am
Follow the steps explained in my previous answer.

http://www.jiskha.com/display.cgi?id=1270449424

If you are just looking for numbers to put into a test or homework, rather than an understanding of how the problem is done, then you have come to the wrong place.

- Physics -
**echem**, Tuesday, April 6, 2010 at 1:40am
First need to convert km/hr to meters/second

(I got around 3333.33 m/s but you might want to double check that)

so 3333.33 is your initial velocity v_i

using kinematics equation:

v_f=V_i+at

y=v_i*t+(1/2)at^(2)

the highest point the projectile reaches is when v_f is zero

so solve for time using the first equation and the known variables

a= 9.8 m/s^2

v_i= 3333.33 m/s

use the time you determined and plug it into the second kinematics equation and then you'll get your max height.

- Physics -
**drwls**, Tuesday, April 6, 2010 at 1:48am
The method described above will not give the correct answer because g is not constant over the large altitude range that the projectile will travel.

Refer to http://www.jiskha.com/display.cgi?id=1270449424

- Physics -
**echem**, Tuesday, April 6, 2010 at 1:56am
That's interesting...because the altitude is so high you have to deal with escape velocity instead of the usual kinematics.

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