Posted by Keith on Monday, April 5, 2010 at 11:14pm.
Well, it has a lot to do with it since instructions for working a limiting reagent problem is just an expanded set of rules (some don't apply) when doing a simpler stoichiometry problem. I have been handy tonight with passing out answers I've given, especially for limiting reagent problems, because I got tired of typing the same thing over and over again (and for the same problem, yet). However, if you got caught in the crossfire, I apologize; but, you can use that set if you ignore the items that don't apply. I worked this problem for someone but here it is again.
a. Convert 66.6 g NH3 to moles. moles = grams/molar mass. Using the coefficients in the balanced equation, convert moles NH3 to moles F2. Now convert moles F2 to grams using g = moles x molar mass.
b. Convert 5.65 g HF to moles. Using the coefficients in the balanced equation, convert moles HF to moles NH3. Now convert moles NH3 to grams. (See the similarity?)
c. Convert 225 g F2 to moles. Using the coefficients in the balanced equation, convert moles F2 to moles N2F4. Convert to grams.
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