I havent been at school for 8 days due to somthing wrong with my heart, but the teachers gave me work. I have no clue how to do them. I really need help please, There all due tomarrow.


Ammonia is formed by reacting nitrogen and hydrogen gases. How many liters of ammonia gas is formed from 13.7 L of hydrogen gas at 93C and pressure of 40 kPa?

Bob Pursley worked this for Dale here.

http://www.jiskha.com/display.cgi?id=1270515133

To solve this problem, we need to use the ideal gas law equation, which is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin. To do this, we add 273 to the Celsius temperature. In this case, 93°C + 273 = 366K.

Next, we can use the ideal gas law to find the number of moles (n) of hydrogen gas. Rearranging the equation, we have n = PV / RT. Substitute the given values into the equation:

n = (40 kPa)(13.7 L) / (0.0821 L/mol*K)(366 K)

The units kPa and L cancel out, leaving us with moles. The gas constant R is given in units of L/mol*K.

Calculating this gives:
n = (40)(13.7) / (0.0821)(366)
n ≈ 5.05 moles

Since the reaction produces ammonia gas in a 1:1 ratio with hydrogen gas, we know that 5.05 moles of hydrogen will produce 5.05 moles of ammonia.

Finally, we can convert moles to liters using the molar volume of an ideal gas at standard temperature and pressure (STP), which is 22.4 L/mol.

So, the volume of ammonia gas formed will be 5.05 moles × 22.4 L/mol.

Calculating this gives:
Volume of ammonia gas ≈ 113.12 L

Therefore, approximately 113.12 liters of ammonia gas will be formed from 13.7 liters of hydrogen gas at the given conditions.