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November 23, 2014

November 23, 2014

Posted by **Anonymous** on Monday, April 5, 2010 at 5:01pm.

f(x) = e^x/1+e^x

find the horizontal and vertical assymptotes?

find the interval whr f is increasing?

Find the inflection point.

Find the interval where the function is concave up.

Find the interval where the function is concave down.

- math (calculus) PLZZZ help! -
**Reiny**, Monday, April 5, 2010 at 6:12pmto have a vertical asymptote, 1 + e^x has to be zero, or

e^x = -1

No value of x makes that statement true, so there is no vertical asymptote.

for x --->∞ , f(x) approaches 1

for x ---> -∞, f(x) approaches 0

so for large +x's, the horizontal asymptote is y = 1

for large -x's the horizontal asymptote is y = 0

f'(x) = [(1+e^x)(e^x) - e^x(e^x)]/(1+e^x)^2

= e^x(1 + 2e^x)/(1+e^x)^2

This will always be positive for any value of x, so the function is increasing for all values of x

- math (calculus) PLZZZ help! -
**bella**, Monday, April 5, 2010 at 6:34pmso would the inflection points be (0,1)?

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