Tuesday

October 21, 2014

October 21, 2014

Posted by **Kelsey** on Monday, April 5, 2010 at 4:39pm.

(a) Find the net gravitational force exerted by these objects on a 57.0 kg object placed midway between them.

N

(b) At what position (other than infinitely remote ones) can the 57.0 kg object be placed so as to experience a net force of zero?

____ m from the 490 kg mass

I figured out the first part is 3.1E-5N

by using the G(m1*m2)/r^2 formula.

but I have no idea how to do it not knowing either distance.

I tried to set the equations equal to eachother and use different variables for both of the distances but the I don't think I can end up with a variable in the answer....

- physics -
**bobpursley**, Monday, April 5, 2010 at 5:57pmb. let x be one distance, and .380-x the other distance. Set the forces at these distances equal.

G190/x^2=G490/(.380-x)^2

solve for x.

**Answer this Question**

**Related Questions**

Physics - objects with masses of 285 kg and a 585 kg are separated by 0.420 m. (...

Physics - Given: The universal gravitational con- stant is 6.672 × 10−11 N...

Physics B - Objects with masses of 105 kg and 528 kg are separated by 0.482 m. A...

Physics B - Objects with masses of 105 kg and 528 kg are separated by 0.482 m. A...

Physics!! - The universal gravitational con- stant is 6.672 × 10−11 N m2/...

Physics - Given: The universal gravitational con- stant is 6.672 × 10−11 N...

Physics - Given: The universal gravitational con- stant is 6.672 × 10−11 N...

Physics - In mathematical language, Newton's Law of Gravity expresses the force ...

physics - Two objects attract each other with a gravitational force of magnitude...

phYsics - Two identical objects each hold a net charge of q = 8e. If the ...