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December 18, 2014

December 18, 2014

Posted by **Omari** on Monday, April 5, 2010 at 8:45am.

a. 78N

b. 119N

c. 197N

d. 392N

The equation I have for average force is "Favg=delta (m*v) / delta time" but I don't think I can apply it directly to this situation.

How do you solve this problem?

- Physics -
**drwls**, Monday, April 5, 2010 at 11:11amYou could use your equation, but would need one more step to be able to use the "give" distance X instead of the "delta time" of deceleration.

The average velocity of the ball while being decelerated is v/2. The "give" distance is thus

X = (v/2)*(delta t)

You will also need

v = sqrt(2gh) = 44.3 m/s

(neglecting air friction)

Favg = m*v/(2x/v) = (1/2)mv^2/X

= 197 N

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